Thursday, 9 February 2012

Limiting Reactants

I. In chemical reactions, usually one chemical gets used up first.
                A. This is known as the limiting reactant
                B. Once the L.R. is used up, the reaction stops
                C. The L.R. determines the quantity of products formed
                D. To find the L.R. assume one reactant is used up. Determine how much of this reactant is used up

Ex.
2.5 mol of CuSO4 reacts with 2.5 mol of NaNO3. A) Determine the L.R. B)Calculate how many moles of NaNO3 are formed.

CuSo4 + 2NaNO3 --> Cu(NO3)2 + Na2SO4

A) 2.5 mol x (2/1*) = 5.0 mol of NaNO3
*What you need over what you have

Since you do not have 5.0 mol of NaNO3 and you only have 2.5 mol of it, the L.R. is NaNo3

B) 2.5 mol x (1/2) = 1.25 mol of NaNO3

Ex.
Determine the L.R. when 1.4 mol of hydrogen reacts with 0.09 mol of oxygen.

2H2 + O2 --> 2H2O

1.4 mol of hydrogen x (1/2) = 0.70 mol of O2

Therefore the L.R. is H2

Ex.
What is the L.R. when 125g of P4 reacts with 320g of Cl2 to form phosphorus trichloride?

P4 + 6Cl2 --> 4PCl3

125g x (1 mol/ 124g*) x (6/1) x (71.0g/ 1 mol**) = 429g of Cl2
* Molar mass of P
**Molar mass of Cl

Therefore Cl2 is the L.R.

Ex. In the formation of water 50g of oxygen react with 60g of hydrogen. Determine the L.R. and theoretical yield.

2H2 + O2 --> 2H2O

50g of O2 x (1 mol/ 32g) x (2/1) x (2.0g/ 1 mol) = 6.25 of H2

Therefore the L.R. is O2

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